IBM Mainframe Forum

Posted: **Thu Jan 19, 2012 9:32 pm**

Can u help me in writing a SORT card which will count the number of similar records clubbed to sum:

My Input file is:

2013-10-01 00:00:00|ABC |-000000100.15
2013-10-01 00:00:00|ABC |+000000200.15
2013-11-01 00:00:00|DEF |+000000200.15
2013-11-01 00:00:00|DEF |+000000100.15
2013-11-02 00:00:00|XYZ |+000000250.15
2013-11-02 00:00:00|XYZ |+000000400.15

I need an output which will do the following:

2013-10-01 00:00:00|ABC |+000000100.00|2
2013-11-01 00:00:00|DEF |+000000300.30|2
2013-11-02 00:00:00|XYZ |+000000650.30|2

Here, 2 records for ABC from input file were added and so that count is displayed after each unique record.

Can I have the SORT card for getting the same?

Thanks much!
With Regards,
Sushmita V

Posted: **Thu Jan 19, 2012 10:08 pm**

sushmita V,

Assuming that your data is already sorted on the key (abc, def, xyz...) the following DFSORT JCL will give you the desired results

Select all

//STEP0100 EXEC PGM=SORT
//SYSOUT DD SYSOUT=*
//SORTIN DD *
----+----1----+----2----+----3----+----4----+----5----+----6----+---
2013-10-01 00:00:00|ABC |-000000100.15
2013-10-01 00:00:00|ABC |+000000200.15
2013-11-01 00:00:00|DEF |+000000200.15
2013-11-01 00:00:00|DEF |+000000100.15
2013-11-02 00:00:00|XYZ |+000000250.15
2013-11-02 00:00:00|XYZ |+000000400.15
//SORTOUT DD SYSOUT=*
//SYSIN DD *
SORT FIELDS=COPY
OUTFIL REMOVECC,NODETAIL,
SECTIONS=(21,3,
TRAILER3=(1,25,TOT=(26,13,SFF,EDIT=(STTTTTTTTT.TT),SIGNS=(+,-)),
'|',COUNT=(M11,LENGTH=2)))
//*

This will produce

Select all

2013-10-01 00:00:00|ABC |+000000100.00|02
2013-11-01 00:00:00|DEF |+000000300.30|02
2013-11-02 00:00:00|XYZ |+000000650.30|02

Posted: **Fri Jan 20, 2012 10:17 am**

Hi skolusu,

It worked! Thanks much.

With regards,
Sushmita V

IBM Mainframe Forum

Count of Records row wise.

Count of Records row wise.

Re: Count of Records row wise.

Re: Count of Records row wise.