IBM Mainframe Forum

Hi All,


I am trying to invoking a jcl program which I passed in my rexx code.
I am trying to achieving this by using "QUEUE" command, but it not working. Below is the snippet


I am executing this rexx by giving 'ex' command infront of the member name.

Many mistakes here:
1 - no such thing as a "JCL program" - JCL describes a job specification including programs to be executed
2 - saying it is not working means absolutely nothing. You MUST say how it is not working (what you expect to happen and what did happen)
3 - You are not submitting anything just putting items on the queue
4 - make submit a procedure and CALL it.
5 - only need 1 EXIT - the second, once you change SIGNAL to CALL should be a RETURN
6 - Read the Rexx manual from start to finish - in particular the keywoerds that you have used.
7 - search the forum for how to properly submit a job via the queue.
8 - TSO is the default address space so you do not need to use ADDRESS TSO
9 - "IF x THEN y" not "IF x THEN DO y END"
10 - "IF x THEN DO y; z; END"
That is enough tutoring.

Why oh why do people insist on writing instream JCL statements to submit.

Because they can - or cannot, in this case!

Thanks NicC,

I am working on points.

Hi Expat,

In my case, I am instream jcl because I need to pass parameter in my jcl which should append in my jcl statement and then it will execute.

Which is easily accomplished using ISPF file tailoring too

The recommended method for generating jobs is ISPF skeleton services. Having said that, I don't have a problem with people generating JCL inline in the program and submitting directly, as usual it depends on the situation.
And now to the program in question, it can be simplified to something like this:

But you really need to work your way through the REXX reference and the TSO command reference manuals.